# -*- coding: utf-8 -*-

"""
#算法说明：要求字符串输入，现将字符串差费为整数部分和小数部分生成list[整数部分,小数部分]
#将整数部分拆分为：[亿，万，仟]三组字符串组成的List:['0000','0000','0000'](根据实际输入生成阶梯List)
#例如：600190000010.70整数部分拆分为：['600','1900','0010']
#然后对list中每个字符串分组进行大写化再合并
#最后处理小数部分的大写化
"""


class ChineNumber:
    cdict = {}
    gdict = {}
    xdict = {}

    def __init__(self):
        self.cdict = {1: u'', 2: u'拾', 3: u'佰', 4: u'仟'}
        self.xdict = {1: u'元', 2: u'万', 3: u'亿', 4: u'兆'}  # 数字标识符
        self.gdict = {0: u'零', 1: u'壹', 2: u'贰', 3: u'叁', 4: u'肆', 5: u'伍', 6: u'陆', 7: u'柒', 8: u'捌', 9: u'玖'}

    def csplit(self, cdata):  # 拆分函数，将整数字符串拆分成[亿，万，仟]的list
        g = len(cdata) % 4
        csdata = []
        lx = len(cdata) - 1
        if g > 0:
            csdata.append(cdata[0:g])
        k = g
        while k <= lx:
            csdata.append(cdata[k:k + 4])
            k += 4
        return csdata

    def cschange(self, cki):  # 对[亿，万，仟]的list中每个字符串分组进行大写化再合并
        lenki = len(cki)
        i = 0
        lk = lenki
        chk = u''
        for i in range(lenki):
            if int(cki[i]) == 0:
                if int(cki[i + 1]) != 0:
                    chk = chk + self.gdict[int(cki[i])]
            else:
                chk = chk + self.gdict[int(cki[i])] + self.cdict[lk]
            lk -= 1
        return chk

    def cwchange(self, data):
        cdata = str(data).split('.')
        cki = cdata[0]
        i = 0
        chk = u''

        cski = self.csplit(cki)  # 分解字符数组[亿，万，仟]三组List:['0000','0000','0000']
        ikl = len(cski)  # 获取拆分后的List长度

        # 大写合并
        for i in range(ikl):
            if self.cschange(cski[i]) == '':  # 有可能一个字符串全是0的情况
                chk = chk + self.cschange(cski[i])  # 此时不需要将数字标识符引入
            else:
                chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i]  # 合并：前字符串大写+当前字符串大写+标识符
                chk = chk + u'整'
        else:
            i = 0
            chk = u''
            cski = self.csplit(cki)  # 分解字符数组[亿，万，仟]三组List:['0000','0000','0000']
            ikl = len(cski)  # 获取拆分后的List长度

        # 大写合并
        for i in range(ikl):
            if self.cschange(cski[i]) == '':  # 有可能一个字符串全是0的情况
                chk = chk + self.cschange(cski[i])  # 此时不需要将数字标识符引入
            else:
                chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i]  # 合并：前字符串大写+当前字符串大写+标识符

        if len(cdata) > 1:
            # 处理小数部分
            ckj = cdata[1]
            lenkj = len(ckj)
            if lenkj == 1:  # 若小数只有1位
                if int(ckj[0]) == 0:
                    chk = chk + u'整'
                else:
                    chk = chk + self.gdict[int(ckj[0])] + u'角整'
            else:  # 若小数有两位的四种情况
                if int(ckj[0]) == 0 and int(ckj[1]) != 0:
                    chk = chk + u'零' + self.gdict[int(ckj[1])] + u'分'
                elif int(ckj[0]) == 0 and int(ckj[1]) == 0:
                    chk = chk + u'整'
                elif int(ckj[0]) != 0 and int(ckj[1]) != 0:
                    chk = chk + self.gdict[int(ckj[0])] + u'角' + self.gdict[int(ckj[1])] + u'分'
                else:
                    chk = chk + self.gdict[int(ckj[0])] + u'角整'

        return chk
